CHALLENGE Α52Ω.4

(BOB TO A.C.A.)

XXXXHHXXXXXOXXXXXOOOO

XXXXHHHHEEEEIIOOOOXXXX

XIIXXXXX HHXXXXXXXOOOOXX

@HOOXXXX@IIIIEEEEIIIIXOOO 

XXXXEEEEEEHHXXXXXOOO@

HHHHHHXXXXXOOOXXXXHHX

XXXXIXXXOOOEEEEttXXXXXOX

OOOOXII IIIEEEEIIIIXttHHOOO

EEIIIHXIOIE@OOEEXXXttHOOH

IIOO@OOHHXXIIIOOOIII/XXHOO

OXIIOOO@XXIIOOOXEEEHHEOO

OX//EEEEIIIXXXIOOOEE1799

CHALLENGE Α51Ω.2

(BOB TO ALICE)

I+9YIIIIENNNΔΡΡΡΕSΟΟ

5ΡΡΡ586ΑCPPPΩ25Ν5ΡΡΑΧ

ΧΥC6+9HXX6H8PPA28PP56

HXX6335AXXP22NNSC+EE

YPNNNY+C11OOIII73XX52II

CHALLENGE 2834.1

(ONE MORE SIMPLE UNBREAKABLE CRYPTOGRAM FROM BOB.TO ALL THE WORLD CODEBREAKERS.CAN ANYBOBY SOLVE AND THIS???)

2-05-1-0-0-2-2-0-3-2-0-5-7-2-0-1-7-0-0-2-2-2-0

-0-5-7-1-0-7-1-9-0-4-3-0-6-2-9-1-0-5-3-9-4-1-0-

0-3-4-0-0-2-2-1-9-1-0-9-7-0-0-7-0-3-1-0-0-2-2-

0-9-2-0-0-1-0-6-2-0-7-7-5-0-0-2-5-0-0-2-0-0-5-

0-0-1-5-0-7-5-0-0-2-0-4-4-1-0-7-0-9-2-0-0-1-1-

0-0-2-2-4-0-0-7-2-4-0-6-1-4-2-9-7-3-1-9-0-7-5-

4-1-0-0-0-2-5-6-0-0-7

1799

CHALLENGE Α12Ω.1

(PAGES FROM BOB'S CHAPTER ABOUT

IMAGE-CIPHERING.

PART III.)

ceσh72Fλgδ2

Outaua nao cya kapura ceoka mapo feaka orua keneasa tas koptos tae tapilae.

ΨωΧΩ:8δSζΡΙΠυFiλρς

...orua keneasa tseamopae.Vliri :(PIΠυ).Onocine

tseamopae vliri:(8δζSPIΠυ).On rapestiqua te sunele:(Fi)teti ihaeci korane asco cite opeastipe

hipea.On te:(λρς)ihaeci korane asco cite dixea hipea.On uanao orecene cina a irea mapofae:(ΨωΧΩ:)teti ihaeci ino tsolo kycine kao korista pocine tsea mape.

mεΔΦΑ8ΩΡΒΕbΜΘγαιη

...ines ommilae rae paresto tivua ciftipo kao hirya

inon toruano rapeseu hecine onqapyre meno teascine.Rapi rua no mapoftaen citan suapo rae dea hnitao.

ΞλχΘυac2

Outaua nao cya kapura ceaka mapo feaka orua keneasa ines cotea ae.

SUNIHEAGITAO.

END PART III.

1799