Monday, October 21, 2019

CHALLENGE 0530.1

57+#0 αξ6\6 /%:# #.6\ Φ%:\ 90=907#
αξ9 ξ4ε% 570\.9 1%6#0 +.6= Φ%-\.7
23 ξ.:\ Φ%-α-9 4%-# #\86160-8 -57:/ω
80%=:Γ61.δ1+%Δο64#/6% |%-Φ 90|6
1:/α3 90= 5|7=5 #08=η8/ 574 802/8| etc
p.s.all protocols is from my manuscript.
takes time to make the proper adjustments
for the blog publishing...1799

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