Monday, November 25, 2019

CHALLENGE Α40Ω.2

(BOB'S OLD CRYPTOGRAM)*
Λ8(8|3.5|4=6+8-6Γ7Χ1231(8+9/1257:12+5Ι8Λ
32Ο/4.8ΛΛ12Ο5Γ94Ι(Χ129=9.3Ο5+8/3Ο9Ο9Χ
4ΛΟ7/69Ο9959+8/3097Γ9/-69Χ418Λ8+9i8/6X
8+35S3O69(9X9ΛΓ9<35i5S4/79=9i7X41
*[back from 2000's]

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